How do I prepare 2-(3-azido-3-oxopropoxy)ethyl methacrylate from methacrylic acid?

I am having some trouble finding a proper synthesis route for the following product.

Originally, I was thinking of reacting methacrylic acid with a large excess of ethylene glycol (along with an acid catalyst), in accordance with Fischer esterification, to obtain the following structure.

I subsequently thought of reacting a base such as sodium hydride, NaH, with the alcohol group (removing its ‘H’) in the hopes of connecting it to the other fragment, which I thought would contain an alkyl halide. However, I was unsure how realistic this step might be due to the following concern: couldn’t the hydride ion, which is a very strong base, attack the ester group instead of the alcohol (despite the alcohol having the lower pKa of the two groups)?

To get around this, I attempted a synthesis, pictured below, starting from ethylene glycol. My main concern with this, however, is the potential for intramolecular Fischer esterification instead of, as depicted, the esterification taking place through methacrylic acid and the acid catalyst (e.g., HCl). How valid is this concern? Additionally, please identify any mistakes I may have made in my synthesis and suggest improvements, even if you have a different synthesis route in mind.