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How was the Cobb Douglas function derived?

Economics Asked by Marcelo Enciso Jure on March 18, 2021

In economics and econometrics, the Cobb–Douglas production function is a particular functional form of the production function, widely used to represent the technological relationship between the amounts of two or more inputs (particularly physical capital and labor) and the amount of output that can be produced by those inputs. The Cobb–Douglas form was developed and tested against statistical evidence by Charles Cobb and Paul Douglas during 1927–1947.

How we get the formula $f(K,L)=AK^aL^{1-a}$? How we get that $K$ must be elevated to some factor "$a$" and this must be multiplied by $L$ elevated by some factor "$1-a$"? What is the proof of this formula? I can’t find an answer to this questions i search it a lot.

Update.
I found an article that shows how to deduce it, but i don’t understand some steps, could someone help me? Here goes the link:

https://www.studocu.com/en-gb/document/kings-college-london/mathemtics-for-economists/lecture-notes/cobb-douglas-revision/4229598/view

In these terms, the assumptions made by Cobb and Douglas can be stated as follows:

  1. If either labor or capital vanishes, then so will production.
  2. The marginal productivity of labor is proportional to the amount of production per unit of
    labor.
  3. The marginal productivity of capital is proportional to the amount of production per unit of
    capital.

Solving.
Because the production per unit of labor is $frac{P}L$
, assumption 2 says that:

$$frac{∂P}{∂L} = αfrac{P}L $$

for some constant α. If we keep K constant($K = K_0$), then this partial differential equation
becomes an ordinary differential equation:

$$frac{dP}{dL} = αfrac{P}L $$

This separable differential equation can be solved by re-arranging the terms and integrating both
sides:

$$int frac{1}P , dP = αint frac{1}L , dL$$
$$ln(P)=α*ln(cL)$$
For example here, from where it comes the constant "c"?, then following:
$$ln(P)=ln(cL^α)$$
$$P(L,K_0)=C_1(K_0)L^α$$
where $C_1(K_0)$ is the constant of integration and we write it as a function of $K_0$ since it could
depend on the value of $K_0$.

2 Answers

What is the proof of this formula?

There is actually no proof for what the production function should be. There are infinite many possible production functions and to discover which one is the most appropriate we need to make some empirical observations. In different cases different production functions are appropriate. Cobb-Douglas is popular production function but I seen many others as well.

What you provide below in your update is not so much of a proof that production has to be Cobb-Douglas rather its a proof that if we make some specific assumptions about production (which although quite general might not always necessary hold actually) we get function that is Cobb-Douglass.

$ln(P)=α∗ln(cL)$ For example here, from where it comes the constant "c"?,

the $c$ is an integration constant. Whenever, you have indefinite integrals you have to add some constant $c$ to the solution because constants get eliminated during differentiation we can never know if there was or wasn't some constant previously so after integrating we always add $c$.

In this case when you integrate this separable differential equation the solution would actually look like:

$$ln(P)= alpha (ln(L) + C) impliesln(P)= alpha ln(cL) | C= ln(c) $$

(actually the variables should even be in absolute values - but since the function is only defined for non-negative values of $P,L$ and $K$ we can omit them).

Correct answer by 1muflon1 on March 18, 2021

If one reads the original article by Cobb and Douglas (1928), https://www.aeaweb.org/aer/top20/18.1.139-165.pdf ,

one will find at the end of page 152 that the authors stress that they took into account two properties that had been theoretically discussed in the past:

  1. That production exhibits constant returns to scale, meaning that doubling all inputs will double output.

  2. That both production inputs are necessary for production, so output should be zero when either one is zero.

To satisfy the 2nd property, they chose the multiplicative form. Given this, to satisfy the first property they had to make the sum of the exponents equal unity, so $a$, and $1-a$. We have $0<a<1$ so that output responds positively to each output.

The existence of the constant $A$ in $Q = AK^aL^{1-a}$ takes care of two things: any "units of measurement" issues but also, the average of any other forces that may contribute to output.

Answered by Alecos Papadopoulos on March 18, 2021

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