# compute the maximum resisting torque that can be overcome by the system at the shaft axis

Engineering Asked by dumisani mthethwa on December 12, 2020

A 2Nm motor M is used to drive the system through a gear drive and a chain drive. the overall reduction ratio is to be between 16:1 and 18:1, and at an output speed of 6rpm.

As Yaniv Ben David states this post needs some clarification. Add a sketch and some more information.

Assuming "shaft axis" is the output shaft and the transmission goes from fast at motor shaft to slow at output shaft the maximum torque is:

$$T_{out,max} = i cdot T_{mot,max} = 32 Nm dots 36 Nm$$ for 'typical' electric motors at low speed.

Considering a rough estimate 10% losses in the drive train, this means you get approx. 29 Nm of torque on the output shaft.

Answered by M.Bauer on December 12, 2020

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