Mathematica Asked on January 2, 2022
If we have two functions $G,F:mathbb R^2tomathbb R^2$ then the mechanism
$Fcirc G(x,y)=F(G(x,y))$ gives us a new map $Fcirc G:mathbb R^2tomathbb R^2$ called its composition.
In a "schematic" view, and with two functions for an example,
we would write
$$
left(begin{array}{c}x\yend{array}right)
stackrel{G}to
left(begin{array}{c}x^2y\2yend{array}right)qquad {rm and}qquad
left(begin{array}{c}x\yend{array}right)
stackrel{F}to
left(begin{array}{c}x-y\xend{array}right)
$$
then
$$
left(begin{array}{c}x\yend{array}right)
stackrel{Fcirc G}longrightarrow
left(begin{array}{c}x^2y-2y\x^2yend{array}right).
$$
How could this process be programmed in Mathematica12?
1 Asked on July 7, 2021 by jo-mo
1 Asked on July 7, 2021 by azzurro94
2 Asked on July 7, 2021
1 Asked on July 7, 2021 by jeremy-lindsay
4 Asked on July 6, 2021 by igunnarsson
3 Asked on July 5, 2021 by sea-cucumber
calculus and analysis expression manipulation simplifying expressions
1 Asked on July 5, 2021 by mathisfun_
1 Asked on July 5, 2021 by bananach
1 Asked on July 5, 2021
1 Asked on July 5, 2021
code request diophantine equations equation solving plotting sets
3 Asked on July 5, 2021 by chyanog
2 Asked on July 4, 2021
0 Asked on July 4, 2021
1 Asked on July 4, 2021
Get help from others!
Recent Answers
Recent Questions
© 2023 AnswerBun.com. All rights reserved. Sites we Love: PCI Database, UKBizDB, Menu Kuliner, Sharing RPP