Trouble with ParametricPlot and custom options

Consider the following code:

Options[pl] = {lim->{0,1}};
pl[n_, OptionsPattern[]] := Plot[x^n, Join[{x}, OptionValue[lim]] ]

This function works as expected on 12.0: running something like pl[2] produces a plot over $[0,1]$, while pl[2, lim->{2,3}] uses the given limits.

But if I instead use ParametricPlot, as in

Options[pl] = {lim->{0,1}};
pl[n_, OptionsPattern[]] := ParametricPlot[{x,x^n}, Join[{x}, OptionValue[lim]] ]

then pl[2] just gives

System`SampledPlotsDump`iParametricPlot[{x, x^2}, Join[{x}, OptionValue[pl, {}, lim]]]

with a similar error message when explicitly including the option. What could be going on here? Why does ParametricPlot behave differently from Plot?