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Derivative of random normal times indicator function

Mathematics Asked by ForumWhiner on November 2, 2021

I have to find $frac{dE[f(X)]}{dX}$ where $f(X) = X1_{X>a}$ where $X sim N(0,1)$ , $1_{X>a}$ is an indicator function taking value 1 if $X>a$ and $0$ otherwise, and $a$ is some constant. I have trouble understanding how to differentiate a random variable (standard normal in this case). On the top of it, an indicator function of random variable is involved.

My approach: Use simple chain rule first and get $frac{dE[f(X)]}{dX} = E[Xdelta_{X} + 1_{X>a}]$ where $delta_{X}$ is the delta function. Is this in the right direction? Any hint is appreciated.

One Answer

$E(f(X))=int_a^{infty} x phi (x)dx$ where $phi$ is the standard normal density. The derivative of this w.r.t. $a$ is $-aphi(a)=-frac a {sqrt 2pi} e^{-a^{2}/2}$.

Answered by Kavi Rama Murthy on November 2, 2021

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