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dimension of a irreducible representation

Mathematics Asked by Myanklana on December 29, 2021

Let G be a group and A an abelian subgroup of G. I want to prove that for each irreducible representation $p$ we have that $dim(p)leq [G:A]$.
I proved that for each subspace $p(A)-$invariant $W$, $W_0= sum_{g in G}p(g)(W)$ is a p(G)-invariant of V (hint of the professor) and that for a abelian finite group, each irreducible representation has dimension 1.
But how can i go on? I wish i can tell more of what i did in this question but i honestly have no idea how to proceed.I was thinking in the canonical decomposition of a representation, considering the subspaces W,but after some writing it seems non-sense.
Any help are welcome.
Ps:my representation theory course uses only knowlegde of theory of groups, not modules or other stuff.

One Answer

You need some assumption on your group and the coefficient field.

I think the idea is to find a non-zero vector on which the abel group acts as a character. Then the remaining things work through: the representation is generated by the vector (as it is irreducible). As the abel subgroup acts on it as a character, we get a spanning set of the representation of order smaller than or equal to [G:H].

For example it is the case if your group is finite and the representation is taking coefficients in an algebraically closely field.

Answered by Peng on December 29, 2021

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