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Symplectomorphism and Hodge decomposition

Mathematics Asked on December 3, 2021

Let $X$ be some holomorphic symplectic manifold. This means we have choosen some $omegain H^{2,0}(X).$ If $f:Xrightarrow X$ is a symplectomorphism, then we have by definition
$$f^*omega=omega.$$
A symplectomorphism $f^*$ has an eigenvalue $1$ on $H^{2,0}(X)$. However, as was pointed out by Michael Albanese in the comments, this is not a sufficient condition, even if we assume that $X$ has a symplectic form. My question is if there exists a cohomological criterion for an endomorphism to be symplectic for some symplectic form.

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