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Yes/ No Is $X$ is homeomorphics to $Y$?

Mathematics Asked on December 6, 2021

$X={(x,y) in mathbb{R^2}: x^2+y^2=1 }$ and $Y={(x,y) in mathbb{R^2}: x^2+y^2=1 } cup {(x,y) in mathbb{R^2}: (x-2)^2+y^2=1 } $ be the subspaces of $mathbb{R}^2$

Now my question is that

Is $X$ is homeomorphics to $Y$ ?

My attempt : Yes

Both $X$and $Y$ are connected and compact

Now by using the theorem connected subspaces of connected sets is connected

So $X$ is homeomorphics to $Y$

Is its true ?

One Answer

No. The set $X$ is a circle. It is connected and it remains connected if you remove any point from it.

But $Y$ is the union of two circles, with a common point, which is $(1,0)$. If you remove that point from $Y$, what you get is disconnected.

So, $X$ and $Y$ are not homeomorphic.

Answered by José Carlos Santos on December 6, 2021

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