Physics Asked by Jean-Michel Tengang on August 5, 2020
To the question regarding the relation between the energy of a photon (E = hf) and the energy of the associated electromagnetic wave, I read somewhere that the energy of an electromagnetic wave is Nhf, N representing the number of photons per second that pass through a unit area. How could the electromagnetic wave associated with a single photon produce several photons? If I read it wrong and it isn’t, how can we represent the electomagnetic wave associated with a single photon and what would be its energy as a function of its frequency.
Regards
The energy of a single photon is $E=hf$ which also corresponds to an electromagnetic wave of frequency $f$. If the beam of light consists of multiple photons, then the total energy of the beam of light equals the number of photons in the light beam $times$ the energy of a single photon: $E_{tot}= Nhf$. In the wave framework, this can be seen as the superpostion of all the $N$ electromagnetic waves of frequency $f$. This resulting superposition is also a wave.
So, it can be that the total electromagnetic wave consists of the superposition of $N$ "fundamental" electromagnetic waves. Here, the $N$ "fundamental" electromagnetic waves correspond to the $N$ photons.
Correct answer by Frederic on August 5, 2020
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