How do two light beams, one squeezed in phase and the other in amplitude, superposed on a beamsplitter, result in an EPR entangled state?

Physics Asked by Quantum Journalist on December 25, 2020

I have found this information in Section 4 of this paper:

Also on Wikipedia

And here in Figure 1

That combining two squeezed light beams with a phase difference of 90 degrees (pi/2 radians) on a beamsplitter and will generate two entangled beams at the output that can be measured with homodyne detection, their quantum uncertainties in phase and amplitude will be correlated.

Here is a more general description of states entangled in phase and amplitude called continuous variable entanglement

And I do not understand the logic behind it. Bell state measurement is supposed to be probabilistic, for example when swapping entanglement between two photon pairs entangled in polarization emitted by a nonlinear crystal.

Here it says continuous variable entanglement is deterministic, as opposite to probabilistic. How is it possible?

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