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In a collision of two billiard balls, is there a threshold energy that is required in order to create a black hole?

Physics Asked by asking_anonymously on January 5, 2021

In a comment on this answer, user PM 2Ring says,

If two billiard balls have enough kinetic energy in their centre of mass frame they can create a black hole, but the amount of KE required is insane, as I mentioned here. (And even if you had access to such energy I don’t know how you’d actually impart it to the balls)

The comment is linked to this answer.

Is there in fact a classical threshold energy for this process, and if so, what is it?

One Answer

No, classically there is no threshold energy for such a process. In an asymptotically flat spacetime, the ADM mass(-energy) is conserved, and classically there is no minimum mass for a black hole. Therefore if the pool balls each have mass $M$, and in addition there is kinetic energy $epsilon$ in the center of mass frame, then the collision can lead to the creation of a black hole with mass $2M+epsilon$. The value of $epsilon$ can be small or even zero without violating conservation of mass, so there is no kinematic threshold for this process.

Of course, there are dynamical reasons why this will not happen. For example, if we know the mass and Young's modulus of a pool ball, then we can estimate the compression of the balls in the collision. This does not result in compression to anything like the Schwarzschild radius of a black hole with mass $2M$. But this is a dynamical argument contingent on the details of the process, not a kinematic threshold.

Answered by asking_anonymously on January 5, 2021

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