Physics Asked by coolcat29 on December 13, 2020
As far as I know, to observe the photoelectric effect, one has to expose a metal surface to high-energy radiation. But what happens if the surface has a surplus of electrons? What is the energy needed to knock of those? Would a lower frequency be sufficient to produce the same effect?
When light falls on the photoelectric surface, photoelectric radiations are emitted, when the energy is more than the work function i.e when more electrons are made to fall on the photoelectric surface,it will go beyond the work function and electrons will be emitted normally.
No,there will be not the same effect because, $f=frac1lambda$,where wavelength is inversely proportional to the frequency.
Answered by user113214 on December 13, 2020
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