Potential of a conductor

Physics Asked by Vibhu Mishra on October 12, 2020

When a charge is placed on a conductor why and how does it potential increase?

It was given in my book that when a charge is placed on a Conductor its potential increase. But why does this happen?

One Answer

When you place the charge Q on the conductor, it will increase the electric field around it. Whereas electric potential is directly proportional to the electric field (E = V / r) (where r is the distance from the conductor).

           E = V / r   ===> V = E * r

from this expression its clear when you increase the electric field by adding charges, it will increase the electric potential as well.

Answered by abinath on October 12, 2020

Potential of a conductor

One Answer

Add your own answers!

Related Questions

Apparent superluminal signals, is it as simple a variation on the following?

Adding a total time derivative term to the Lagrangian

Eddy current brake with superconductor

Understanding the following THz-to-optical conversion scheme

Why doesnt a wet circuit work

Massless Kerr black hole

How to handle a Displacement Operator which parametrically depends on a second coordinate?

Lorentz boost transformations form a group?

Deriving thermodynamic quantities from partition functions

Effect of frequency on magnitude of photo current

Path integral with initial definite momentum

Heat to Latereal Motion Converter

How is $Delta m^2_{12}$ is identified with the solar mixing angle?

Pressure difference along horizontal in accelerated fluids

OPE in linear dilaton theory

Residue of the Fermi Distribution Function

Calculating forces via Feynman diagrams?

Damped harmonic Oscillator Lagrangian equivalence

Is idempotency, $rho^2=rho$, a necessary and sufficient condition for $rho$ to be a pure state?

Apsidal precession

Ask a Question