Find button class with Selenium on Python

Question

Please I'm quite a selenium newbie and I really need help to get the data for my thesis. I scrapping the marketplace from this url https://www.tokopedia.com/sunxin I want to get the data from the button called "Info Toko", if user click this will shown a pop up content The original source code for this button is: I've tried to get the element by xpath, classname, link text but still not working. driver.find_element_by_link_text('Info Toko') Always get error message like this A very big thank you for anyone who can give a suggest or advice to get this element

PDHide · Answer

When ever you use a method read its documentation :
https://selenium-python.readthedocs.io/locating-elements.html
continue_link = driver.find_element_by_link_text('Continue')
continue_link = driver.find_element_by_partial_link_text('Conti')

This two element locators identifies the element only using link text.
In selenium a link is "an anchor tag" , an anchor tag is used wrap a href link
in your case its a button tag and not a anchor 'a' tag, so link text method won't work
use xpath , css or class
xpath:
driver.find_element_by_xpath('//button[text()="Info Toko"]')

css:
css to find using class
driver.find_element_by_css_selector('button.css-rhf1fq-unf-btn.e1ggruw00')

class:
driver.find_element_by_class_name('css-rhf1fq-unf-btn e1ggruw00')

Mohamed Sulaimaan Sheriff · Answer

Try by using xpath selector
In which you want to change your selector code as shown below
driver.find_element_by_xpath('//div[@class="css-ais6tt"]//button[3]')
This will work

Find button class with Selenium on Python

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