How to use "." as a wildcard inside "string" instead of pattern?

Question

I have this:
incompleted_string1 = "Thom"
incompleted_string2 = "s Mueller naive"
entire_string = 'Thom.s Mueller naive'  # <= dot means any char!!! I dont know which char is it
pattern = "mas M"

I would like to know if "mas M" if present inside entire_string. I do not care if "." is equal to "a" or something else. I cannot change the pattern string!
re.findall("mas M", entire_string)

This returns [] I'd like to have "mas M" but True will be enough
Thank you for your help

mad_ · Answer

The another approach could be to have all the possible combinations of pattern
bool(re.search(pattern  + "|"+ "|".join([pattern[0:i] + '.' + pattern[i+1:] for i in range(len(pattern))]), entire_string))

Wiktor Stribiżew · Answer

You can replace each char in the pattern with [ + this char + . + ]:
bool(re.search("".join([f"[{x}.]" for x in pattern]), entire_string))

The pattern will look like [m.][a.][s.][ .][M.] here, and each can match either the corresponding letter or a dot. See the regex demo.
See the Python demo:
import re
incompleted_string1 = "Thom"
incompleted_string2 = "s Mueller naive"
entire_string = 'Thom.s Mueller naive'  # <= dot means any char!!! I dont know which char is it
pattern = "mas M"
print (bool(re.search("".join([f"[{x}.]" for x in pattern]), entire_string)) )
# => True

How to use "." as a wildcard inside "string" instead of pattern?

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