I am getting error while while using "zappa init'

Question

I am using python 3.8 and zappa 0.51.0. I have installed zappa in a virtual environment and created AWS account also but when I am trying to command "zappa init" its showing error given below

    (.env) D:rough workcrud>zappa init
    Traceback (most recent call last):
      File "c:usersdwipal shriraoappdatalocalprogramspythonpython38Librunpy.py", line 192, in _run_module_as_main
        return _run_code(code, main_globals, None,
      File "c:usersdwipal shriraoappdatalocalprogramspythonpython38Librunpy.py", line 85, in _run_code
        exec(code, run_globals)
      File "D:rough workcrud.envScriptszappa.exe__main__.py", line 4, in <module>
      File "d:rough workcrud.envlibsite-packageszappacli.py", line 44, in <module>
        from .core import Zappa, logger, API_GATEWAY_REGIONS
      File "d:rough workcrud.envlibsite-packageszappacore.py", line 33, in <module>
        import troposphere
      File "d:rough workcrud.envlibsite-packagestroposphere__init__.py", line 586, in <module>
        class Template(object):
      File "d:rough workcrud.envlibsite-packagestroposphere__init__.py", line 588, in Template
        'AWSTemplateFormatVersion': (basestring, False),
    NameError: name 'basestring' is not defined

what is happening and how I can get rid of this error?

amazon web services aws lambda django python zappa

Traycho Ivanov · Answer

The builtin basestring abstract type was removed. Use str instead. The str and bytes types don’t have functionality enough in common to
warrant a shared base class. The 2to3 tool (see below) replaces every
occurrence of basestring with str.

As you are with python version 3.8, use str instead.

I am getting error while while using "zappa init'

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