Javascript Regex, Add space before and after math operators if there is none

Im trying to make the perfect math parser for my discord bot.

Currently I have a simple function parser that takes in a string which has a ton of .replace methods to clear up a bunch of junk or formatting things leftover from discord, or just replaces {} with () and such quality of life things…

var parseArgs = args.toLowerCase().replace(/ -o/g, "").replace(/x/g, "*").replace(/[a-z]/g, "")
    .replace(/{/g, "(").replace(/}/g, ")").replace(/[/g, "(").replace(/]/g, ")").replace(/+=/g, "+")
    .replace(/-=/g, "-").replace(/'/g, "").replace(/`/g, "").replace(/"/g, "");

var origArgs = args.toLowerCase().replace(/`/g, "").replace(/ -o/g, "");

const output = parseMath(parseArgs);

This is nice and all, but If you input an equation like this:
!math 1 + 1aaa+aaaa2{55>>2}

The parser will output:
1 + 1+2*(55>>2)

I want it to output:
1 + 1 + 2 * (55 >> 2)

Which easily gets parsed by my function, but the equation is sent into the chat, and its quite ugly.

Im asking if theres a simple regex formula to check if a math operator (+ - / * x ( ) >> ^ += -= == ===) like those is between any numbers

so 1+2/3(4>>2) and 3>>4===3*4 will turn into 1 + 2 / 3 (4 >> 2) and 3 >> 4 === 3 * 4 respectively.

Edit: I see how crappy my replaces are, so I simplified them:

var parseArgs = args.toLowerCase().replace(/x/g, "*").replace(/ -o|[a-z]|"|'|`/g, "")
    .replace(/{|[/g, "(").replace(/}|]/g, ")").replace(/+=/g, "+").replace(/-=/g, "-");
var origArgs = args.toLowerCase().replace(/ -o|`/g, "");

const parse = (args) => {
  const argsWithOnlyMath = args.replace(/[^d+-/*x()>^=]/g, ' ');
  const spacedArgs = argsWithOnlyMath
    .replace(/s*(D+)s*/g, ' $1 ') // add spaces
    .replace(/ +/g, ' ') // ensure no duplicate spaces
    .replace(/( /g, '(') // remove space after (
    .replace(/ )/g, ')'); // remove space before )
  console.log(spacedArgs);
};
parse('!math 1 + 1aaa+aaaa2(55>>2)');
parse(' 1+2/3(4>>2) ');
parse('3>>4===3*4');

const parse = (args) => {
  const argsWithOnlyMath = args.replace(/[^d+-/*x()>^=]/g, ' ');
  const spacedArgs = argsWithOnlyMath
    .replace(/s*(D+)s*/g, ' $1 ') // add spaces
    .replace(/(/g, ' (') // add space before (
    .replace(/)/g, ') ') // add space after )
    .replace(/ +/g, ' ') // ensure no duplicate spaces
    .replace(/( /g, '(') // remove space after (
    .replace(/ )/g, ')'); // remove space before )
  console.log(spacedArgs);
};
parse('!math 1 + 1aaa+aaaa2(55>>2)');
parse(' 1+2/3(4>>2) *()');
parse('3*()');