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leetcode algorithm edgecase issue

Stack Overflow Asked by stephen1993 on November 7, 2020

I am doing the following problem:

Given the array candies and the integer extraCandies, where candies[i]
represents the number of candies that the ith kid has.

For each kid check if there is a way to distribute extraCandies among
the kids such that he or she can have the greatest number of candies
among them. Notice that multiple kids can have the greatest number of
candies.

Example 1:

Input: candies = [2,3,5,1,3], extraCandies = 3 Output:
[true,true,true,false,true] Explanation: Kid 1 has 2 candies and if
he or she receives all extra candies (3) will have 5 candies — the
greatest number of candies among the kids. Kid 2 has 3 candies and if
he or she receives at least 2 extra candies will have the greatest
number of candies among the kids. Kid 3 has 5 candies and this is
already the greatest number of candies among the kids. Kid 4 has 1
candy and even if he or she receives all extra candies will only have
4 candies. Kid 5 has 3 candies and if he or she receives at least 2
extra candies will have the greatest number of candies among the kids.
Example 2:

Input: candies = [4,2,1,1,2], extraCandies = 1 Output:
[true,false,false,false,false] Explanation: There is only 1 extra
candy, therefore only kid 1 will have the greatest number of candies
among the kids regardless of who takes the extra candy. Example 3:

Input: candies = [12,1,12], extraCandies = 10 Output:
[true,false,true]

Constraints:

2 <= candies.length <= 100 1 <= candies[i] <= 100 1 <= extraCandies <=
50

here is my code and below my code is the error I am getting but it seems right?

const kidsWithCandies = (candies, extraCandies) => {
    let candiesTwo = [...candies]
    candiesTwo = candiesTwo.sort()
    
    let arr = []
    let highestNum = candiesTwo[candiesTwo.length -1]
    
    for(let i = 0; i < candies.length; i++) { 
        if(candies[i] + extraCandies >= highestNum) { 
            arr.push(true)
        }  else { 
          arr.push(false)
        }
    }
    return arr
}

I am getting

71 / 103 test cases passed.
Status: Wrong Answer
Submitted: 3 minutes ago
Input:
[1,10,10,3]
1
Output:
[false,true,true,true]
Expected:
[false,true,true,false]

3 Answers

Use a compare function to sort numbers or they will be in alpha order. By default, the sort() method sorts the values as strings in alphabetical and ascending order.

Simple example

const candies = [4, 11, 22, 2, 1];

console.log('No compare function:', JSON.stringify([...candies].sort()))

candies.sort((a, b) => a - b);
console.log('With compare function:', JSON.stringify(candies))

Correct answer by charlietfl on November 7, 2020

If we'd use sort, the time complexity would be an order of N Log N. Here is an O(N) solution:

const kidsWithCandies = (candies, extraCandies) => {
    let maxCandies = 0;
    const greatest = [];

    for (const candy of candies) {
        (candy > maxCandies) && (maxCandies = candy);
    }

    for (let index = 0; index < candies.length; ++index) {
        greatest.push(candies[index] + extraCandies >= maxCandies);
    }
    return greatest;
};

Answered by Emma on November 7, 2020

By default sort method sorts items alphabetically. You should update from

candiesTwo = candiesTwo.sort()

to

candiesTwo.sort((a, b) => a-b);

for numerical sort.

Answered by SoftDev on November 7, 2020

Add your own answers!

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