List of tuples remove duplicates by first index

I’m having a hard time with this one. I have a list of tuples but am only interested in removing duplicates based on the first item of the tuples.

I need to remove the duplicates from the individual lists by only looking at the first item in the tuple.

I need to compare the lists for duplicates where unique is in uniqueFound and only keep those from unique that are not in uniqueFound, also only interested in the first item of the tuple. The other numbers and values should not be considered. Here is what I came up with, and it’s still passing N1 to the final list when it shouldn’t. There has to be an easier way to do this?

#unique found
uniqueFound = [('N1', '20.3', 1, 58, 14),
         ('N2', '20.1', 1, 44, 14),
         ('N3', '21', 1, 23, 14),
         ('N1', '21', 1, 23, 14),
         ('N5', '33', 1, 34, 14)
         ]
unique = [('N0', '23', 2, 22, 1),
         ('N6', '33.1', 1, 25, 11),
         ('N3', '21', 1, 33, 12),
         ('N1', '44', 1, 2, 44),
         ('N7', '33.2', 4, 22, 12),
         ('N7', '3.2', 2, 21, 132)
         ]

#Remove duplicates
uniqueFound = dict((x[0], x) for x in uniqueFound).values()
unique = dict((x[0], x) for x in unique).values()

fmatches=[]
uniquefinal = []

for x in uniqueFound:
    for y in unique:
        if x[0] == y[0]:
            fmatches.append(y)
        else:
            continue
fmatches = dict((x[0], x) for x in fmatches).values()
for x in unique:
    for y in fmatches:
        if x[0] == y[0]:
            continue
        else:
            uniquefinal.append(x)
duplicatesrem = dict((x[0], x) for x in uniquefinal).values()
uniqueFinal = list(duplicatesrem)
print(uniqueFinal)

which yields

[('N0', '23', 2, 22, 1), ('N6', '33.1', 1, 25, 11), ('N3', '21', 1, 33, 12), ('N1', '44', 1, 2, 44), ('N7', '3.2', 2, 21, 132)]

What I’m going for (in unique but not in uniqueFound):

[('N0', '23', 2, 22, 1), ('N6', '33.1', 1, 25, 11), ('N7', '3.2', 2, 21, 132)]

Thanks for your help.

uniqueFound = [('N1', '20.3', 1, 58, 14),
         ('N2', '20.1', 1, 44, 14),
         ('N3', '21', 1, 23, 14),
         ('N1', '21', 1, 23, 14),
         ('N5', '33', 1, 34, 14)
         ]
unique = [('N0', '23', 2, 22, 1),
         ('N6', '33.1', 1, 25, 11),
         ('N3', '21', 1, 33, 12),
         ('N1', '44', 1, 2, 44),
         ('N7', '33.2', 4, 22, 12),
         ('N7', '3.2', 2, 23, 1)
         ]

aux1 = set(e[0] for e in uniqueFound)
aux2 = set()
result = []
for e in unique:
    e0 = e[0]
    if e0 in aux1: continue
    if e0 in aux2: continue
    aux2.add(e0)
    result.append(e)
print(result)

found = {i[0] for i in uniqueFound}
dct = {k: v for k, *v in unique if k not in found}
[(k, *v) for k, v in dct.items()]
# [('N0', '23', 2, 22, 1), ('N6', '33.1', 1, 25, 11), ('N7', '3.2', 2, 23, 1)]

drop = {t[0] for t in uniqueFound} # set comprehension

# build a conditional list comprehension
uniqueFinal = [e for e in unique if e[0] not in drop]