Python, change a var by a string

Question

I have multiple type1 = Label(image=type_none) and get a list ['Ground', 'Rock', 'Water'] and want to change it to
type1 = Label(image=type_Ground)
type2 = Label(image=type_Rock)
etc. The type_Rock are already defined, and contain Data i want to Display.
So i am looking for a way to dynamically change the Variable. Something like this.
for i in range(0, len(type_list)):
    type{i} = Label(image=type_{type_list[i]})

In the end it should update the Images of the Labels 1 through X. I am still a beginner and cant find a way to do this. I would post the full code, but it is large and messy. In case you need to know, the Image i have to define as self.type_ground = ImageTk.PhotoImage(Image.open("img/Ground.png").resize(self.type_size))
Thanks for your time reading through my Problems :)
Edit: Thanks for the Answers, i initially looked at eval(), and it worked fine, but i ran into some issues and because you all said it was bad practices, i now use dicts and lists containing the Variables.
The Image can be easily created like so: type_img = {"Scaning": ImageTk.PhotoImage(Image.open("img/Scaning.png").resize(type_size))},
but the Tk.Label objects, i needed to handle different.
First i create the Label wtype0 = Label(master, image=type_img["None"]), place it in Tkinter, then store it in a list type_tklist = [self.wtype0]
Then when i want to change the images, i can simply
for i in range(0, len(weak1)):
     self.type_tklist[i].configure(image=self.type_img[weak1[i]])
     self.type_tklist[i].image = self.type_img[weak1[i]]

ADdV · Accepted Answer

This is possible...
This is possible, using the built-in function eval, but it is almost always a very bad idea. Regardless, if you'd want to do this, you could do something like:
for i in range(0, len(type_list)):
    eval('type{} = something'.format(i))

But there are always better options
Instead, consider using a list of types:
types = []
for i in range(0, len(type_list)):
    types.append(something)

which you can then access like types[1].
If you want better "names" for the different types than just numbers, consider using a dict.

Liquid Snake · Answer

If I'm understanding your question correctly, there are a couple of routes to choose in my mind: one using classes and the other using a dictionary. For speed, I will show the method with a dictionary with an enumeration method to get by having to fiddle too much with indices.
data = {}
names = ["Ground", "Rock", "Water"]

for i, type in enumerate(type_list):
   key = names[i] 
   data[key] = Label(image=type)

From here, you can choose the data you want to work with by simply keying the name of the type you're interested in; for instance:
# type1
type1 = data["Ground"]

Please let me know if I misunderstood.

jpear1 · Answer

This is technically possible using Python's eval() function, but it's considered bad programming practice.
Instead of defining your images as type_Rock, type_Ground, I'd recommend creating a dictionary type_images where your key is Rock, Ground, etc.
Your loop would look like:
for t, img in type_images.items():
    type{i} = Label(image=img)

SeYeD.Dev · Answer

you can create string and then use eval()
ex :
    eval(f"type{i} = Label(image=type_{type_list[i]})")

Python, change a var by a string

4 Answers

This is possible...

But there are always better options

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