Understanding the operator "less" or "greater" in assigning value with C++

Question

I used greater than and less than signs and it gives ouput! How it is working ?

int x = 2;
x >= 3;
cout << x;  // output is 2

And also the output is different like this

int x = 2;
x = x > 3;
cout << x;   // output is zero !! HOW ??

assignment operator bitwise operators c++comparison operators relational operators

RobertS supports Monica Cellio · Answer

If you use int x = 2; x >= 3; cout << x; the output is 2 because the result of the x >= 3 operation is discarded (not used) and x remains by the same value as it were initialized. x was not assigned by any value after its initialization. If you use int x = 2; x = x > 3; cout << x; ` x is checked whether it is greater than 3 or not with x > 3. If it is, the value of the expression x > 3 turns 1, if not it turns 0. Comparison operations are boolean expressions. This boolean value is assigned back to x after the evaluation of x > 3. Since x is not greater than 3, the expression x > 3 gains the value 0 and this value is assigned back to x and finally what is printed.

CiaPan · Answer

The expression
x >= 3

is a pure comparison. It tests, whether the value of variable x is greater than, or equals 3. The result is 0 or 1 – for x equal 2 it is zero, false.
Terminating the expression with a semicolon creates a statement. That statement performs a comparison and ...nothing else. The result of comparison is discarded, and the variable x remains unchanged. Hence the observed resulting value 2.

In x = x > 3; the subexpression x > 3 is a comparison. Its result is 1 if the comparison succeedes, 0 otherwise.
Since you initialized x to 2, the result of the comparison is false, i.e. zero.
As a result
x = x > 3;

equivalent to
x = (x > 3);

resolves to
x = 0;

hence the output you observed.

Understanding the operator "less" or "greater" in assigning value with C++

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