Why is df.info().to_csv('File_name.csv') returning error?

import io
buffer = io.StringIO()
df.info(buf=buffer)
s = buffer.getvalue()
with open("df_info.txt", "w",encoding="utf-8") as f:  
f.write(s)

According to the pandas documentation https://pandas.pydata.org/pandas-docs/stable/reference/api/pandas.DataFrame.info.html this is how you can write df.info to a file.

If you wish to write it to a CSV, you can replace the
with open("df_info.txt", "w",encoding="utf-8") as f With with open("df_info.csv", "w",encoding="utf-8") as f

df.info() prints a summary of the dataframe and returns None. And that doesn't have any method to_csv.

But from you question I guess you are looking fro something like this:

with open('output.txt','w') as out:
  df.info(buf = out)

df.info() is a method that doesn't actually return anything. Instead, (from the pandas docs) it "Prints a concise summary of a DataFrame." This means that you are running df.info() (which returns None) and then trying to call to_csv() on that.

Saving df.info() as a csv will be difficult, given the output is actually not a table. It contains a table, but also contains info such as

<class 'pandas.core.frame.DataFrame'>
RangeIndex: 1000000 entries, 0 to 999999
Data columns (total 3 columns):

and

dtypes: object(3)
memory usage: 22.9+ MB

You can save the entire output to a text file as mentioned in the pandas documentation:

with open('info.txt', 'w') as f:
    df.info(buf=f)