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dgroup placing equation number on left side

TeX - LaTeX Asked by Morten Nissov on August 2, 2020

I am using some equations that are auto-generated from a script and they are typeset using breqn functions.

Using dgroup is causing my equation number to be on the left side instead of right. I call the packages in this order, which should be correct as far as I could see from the documentation.

usepackage{amsmath}
usepackage{flexisym}
usepackage{breqn}
usepackage{bm}
usepackage{amsfonts}

The equations being typeset are

begin{dgroup}
            begin{dmath*}
                0=frac{partial }{partial t} y_{2}left(tright)-frac{sinleft(y_{3}left(tright)right)cdot y_{5}left(tright)}{6371}
            end{dmath*}
            begin{dmath*}
                0=frac{cosleft(y_{3}left(tright)right)cdot y_{5}left(tright)}{6371}-frac{partial }{partial t} y_{1}left(tright)
            end{dmath*}
            begin{dmath*}
                0=frac{cosleft(y_{3}left(tright)right)cdot frac{partial }{partial t} y_{2}left(tright)}{sinleft(y_{3}left(tright)right)}-frac{partial }{partial t} y_{1}left(tright)
            end{dmath*}
            begin{dmath*}
                0=y_{6}left(tright)-y_{5}left(tright)
            end{dmath*}
            begin{dmath*}
                0=y_{6}left(tright)-frac{6371cdot frac{partial }{partial t} y_{2}left(tright)}{sinleft(y_{3}left(tright)right)}
            end{dmath*}
            begin{dmath*}
                0=y_{6}left(tright)-frac{6371cdot frac{partial }{partial t} y_{1}left(tright)}{cosleft(y_{3}left(tright)right)}
            end{dmath*}
            begin{dmath*}
                0=y_{4}left(tright)-y_{3}left(tright)
            end{dmath*}
            begin{dmath*}
                0=frac{sinleft(y_{4}left(tright)right)cdot y_{5}left(tright)}{6371}-frac{partial }{partial t} y_{2}left(tright)
            end{dmath*}
            begin{dmath*}
                0=frac{cosleft(y_{4}left(tright)right)cdot y_{5}left(tright)}{6371}-frac{partial }{partial t} y_{1}left(tright)
            end{dmath*}
            begin{dmath*}
                0=frac{cosleft(y_{4}left(tright)right)cdot frac{partial }{partial t} y_{2}left(tright)}{sinleft(y_{4}left(tright)right)}-frac{partial }{partial t} y_{1}left(tright)
            end{dmath*}
            begin{dmath*}
                0=y_{6}left(tright)-frac{6371cdot frac{partial }{partial t} y_{2}left(tright)}{sinleft(y_{4}left(tright)right)}
            end{dmath*}
            begin{dmath*}
                0=y_{6}left(tright)-frac{6371cdot frac{partial }{partial t} y_{1}left(tright)}{cosleft(y_{4}left(tright)right)}
            end{dmath*}
        end{dgroup}

One Answer

Not a solution, but this seems to be a known bug in breqn, see page 5 of the package manual:

enter image description here

So, for now you can't achieve exactly what you want the way you do it. I will check if I can come back with a workaround.

O.K, here is a not-so-elegant workaround:

documentclass{article}
usepackage{amsmath}
usepackage{amsfonts}
usepackage{flexisym}
usepackage{breqn}
usepackage{bm}

begin{document}
begin{equation}
parbox{.9linewidth}{%
begin{dgroup*}
    begin{dmath*}
        0=frac{partial }{partial t} y_{2}left(tright)-frac{sinleft(y_{3}left(tright)right)cdot y_{5}left(tright)}{6371}
    end{dmath*}
    begin{dmath*}
        0=frac{cosleft(y_{3}left(tright)right)cdot y_{5}left(tright)}{6371}-frac{partial }{partial t} y_{1}left(tright)
    end{dmath*}
    begin{dmath*}
        0=frac{cosleft(y_{3}left(tright)right)cdot frac{partial }{partial t} y_{2}left(tright)}{sinleft(y_{3}left(tright)right)}-frac{partial }{partial t} y_{1}left(tright)
    end{dmath*}
    begin{dmath*}
        0=y_{6}left(tright)-y_{5}left(tright)
    end{dmath*}
    begin{dmath*}
        0=y_{6}left(tright)-frac{6371cdot frac{partial }{partial t} y_{2}left(tright)}{sinleft(y_{3}left(tright)right)}
    end{dmath*}
    begin{dmath*}
        0=y_{6}left(tright)-frac{6371cdot frac{partial }{partial t} y_{1}left(tright)}{cosleft(y_{3}left(tright)right)}
    end{dmath*}
    begin{dmath*}
        0=y_{4}left(tright)-y_{3}left(tright)
    end{dmath*}
    begin{dmath*}
        0=frac{sinleft(y_{4}left(tright)right)cdot y_{5}left(tright)}{6371}-frac{partial }{partial t} y_{2}left(tright)
    end{dmath*}
    begin{dmath*}
        0=frac{cosleft(y_{4}left(tright)right)cdot y_{5}left(tright)}{6371}-frac{partial }{partial t} y_{1}left(tright)
    end{dmath*}
    begin{dmath*}
        0=frac{cosleft(y_{4}left(tright)right)cdot frac{partial }{partial t} y_{2}left(tright)}{sinleft(y_{4}left(tright)right)}-frac{partial }{partial t} y_{1}left(tright)
    end{dmath*}
    begin{dmath*}
        0=y_{6}left(tright)-frac{6371cdot frac{partial }{partial t} y_{2}left(tright)}{sinleft(y_{4}left(tright)right)}
    end{dmath*}
    begin{dmath*}
        0=y_{6}left(tright)-frac{6371cdot frac{partial }{partial t} y_{1}left(tright)}{cosleft(y_{4}left(tright)right)}
    end{dmath*}
end{dgroup*}
}
end{equation}

end{document}

enter image description here

Answered by AboAmmar on August 2, 2020

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